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8(4-3)+1=53-3(x-5)
We move all terms to the left:
8(4-3)+1-(53-3(x-5))=0
We add all the numbers together, and all the variables
-(53-3(x-5))+1+81=0
We add all the numbers together, and all the variables
-(53-3(x-5))+82=0
We calculate terms in parentheses: -(53-3(x-5)), so:We get rid of parentheses
53-3(x-5)
determiningTheFunctionDomain -3(x-5)+53
We multiply parentheses
-3x+15+53
We add all the numbers together, and all the variables
-3x+68
Back to the equation:
-(-3x+68)
3x-68+82=0
We add all the numbers together, and all the variables
3x+14=0
We move all terms containing x to the left, all other terms to the right
3x=-14
x=-14/3
x=-4+2/3
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