8(4-x)+6=-6(x-3)-3

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Solution for 8(4-x)+6=-6(x-3)-3 equation: 



8(4-x)+6=-6(x-3)-3

We move all terms to the left:

8(4-x)+6-(-6(x-3)-3)=0

We add all the numbers together, and all the variables

8(-1x+4)-(-6(x-3)-3)+6=0

We multiply parentheses

-8x-(-6(x-3)-3)+32+6=0



We calculate terms in parentheses: -(-6(x-3)-3), so:

-6(x-3)-3

We multiply parentheses

-6x+18-3

We add all the numbers together, and all the variables

-6x+15

Back to the equation:

-(-6x+15)



We add all the numbers together, and all the variables

-8x-(-6x+15)+38=0

We get rid of parentheses

-8x+6x-15+38=0

We add all the numbers together, and all the variables

-2x+23=0

We move all terms containing x to the left, all other terms to the right

-2x=-23

x=-23/-2

x=11+1/2

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