8(4-x)=(7x+2)

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Solution for 8(4-x)=(7x+2) equation: 



8(4-x)=(7x+2)

We move all terms to the left:

8(4-x)-((7x+2))=0

We add all the numbers together, and all the variables

8(-1x+4)-((7x+2))=0

We multiply parentheses

-8x-((7x+2))+32=0



We calculate terms in parentheses: -((7x+2)), so:

(7x+2)

We get rid of parentheses

7x+2

Back to the equation:

-(7x+2)



We get rid of parentheses

-8x-7x-2+32=0

We add all the numbers together, and all the variables

-15x+30=0

We move all terms containing x to the left, all other terms to the right

-15x=-30

x=-30/-15

x=+2

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