8(4b+3)+8=-26+3b

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Solution for 8(4b+3)+8=-26+3b equation: 



8(4b+3)+8=-26+3b

We move all terms to the left:

8(4b+3)+8-(-26+3b)=0

We add all the numbers together, and all the variables

8(4b+3)-(3b-26)+8=0

We multiply parentheses

32b-(3b-26)+24+8=0

We get rid of parentheses

32b-3b+26+24+8=0

We add all the numbers together, and all the variables

29b+58=0

We move all terms containing b to the left, all other terms to the right

29b=-58

b=-58/29

b=-2

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