8(4k+2)=6(6k-7)-3k

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Solution for 8(4k+2)=6(6k-7)-3k equation: 



8(4k+2)=6(6k-7)-3k

We move all terms to the left:

8(4k+2)-(6(6k-7)-3k)=0

We multiply parentheses

32k-(6(6k-7)-3k)+16=0



We calculate terms in parentheses: -(6(6k-7)-3k), so:

6(6k-7)-3k

We add all the numbers together, and all the variables

-3k+6(6k-7)

We multiply parentheses

-3k+36k-42

We add all the numbers together, and all the variables

33k-42

Back to the equation:

-(33k-42)



We get rid of parentheses

32k-33k+42+16=0

We add all the numbers together, and all the variables

-1k+58=0

We move all terms containing k to the left, all other terms to the right

-k=-58

k=-58/-1

k=+58

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