8(4q-5)-7q=1/4r+6

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Solution for 8(4q-5)-7q=1/4r+6 equation: 


x in (-oo:+oo)

8*(4*q-5)-(7*q) = (1/4)*r+6 // - (1/4)*r+6

8*(4*q-5)-(7*q)-((1/4)*r)-6 = 0

8*(4*q-5)-7*q+(-1/4)*r-6 = 0

8*(4*q-5)-7*q-r/4-6 = 0

(4*8*(4*q-5))/4+(-7*4*q)/4-r/4+(-6*4)/4 = 0

4*8*(4*q-5)-7*4*q-r-6*4 = 0

100*q-r-160-24 = 0

100*q-r-184 = 0

(100*q-r-184)/4 = 0

(100*q-r-184)/4 = 0 // * 4

100*q-r-184 = 0

x belongs to the empty set

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