8(4r-3)=-6(r+4)

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Solution for 8(4r-3)=-6(r+4) equation: 



8(4r-3)=-6(r+4)

We move all terms to the left:

8(4r-3)-(-6(r+4))=0

We multiply parentheses

32r-(-6(r+4))-24=0



We calculate terms in parentheses: -(-6(r+4)), so:

-6(r+4)

We multiply parentheses

-6r-24

Back to the equation:

-(-6r-24)



We get rid of parentheses

32r+6r+24-24=0

We add all the numbers together, and all the variables

38r=0

r=0/38

r=0

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