8(4t+1)-11=t-(t+2)

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Solution for 8(4t+1)-11=t-(t+2) equation:



8(4t+1)-11=t-(t+2)
We move all terms to the left:
8(4t+1)-11-(t-(t+2))=0
We multiply parentheses
32t-(t-(t+2))+8-11=0
We calculate terms in parentheses: -(t-(t+2)), so:
t-(t+2)
We get rid of parentheses
t-t-2
We add all the numbers together, and all the variables
-2
Back to the equation:
-(-2)
We add all the numbers together, and all the variables
32t-1=0
We move all terms containing t to the left, all other terms to the right
32t=1
t=1/32
t=1/32

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