8(4t+1)-12=t-(t+3)

Solution for 8(4t+1)-12=t-(t+3) equation:

Simplifying
8(4t + 1) + -12 = t + -1(t + 3)

Reorder the terms:
8(1 + 4t) + -12 = t + -1(t + 3)
(1 * 8 + 4t * 8) + -12 = t + -1(t + 3)
(8 + 32t) + -12 = t + -1(t + 3)

Reorder the terms:
8 + -12 + 32t = t + -1(t + 3)

Combine like terms: 8 + -12 = -4
-4 + 32t = t + -1(t + 3)

Reorder the terms:
-4 + 32t = t + -1(3 + t)
-4 + 32t = t + (3 * -1 + t * -1)
-4 + 32t = t + (-3 + -1t)

Reorder the terms:
-4 + 32t = -3 + t + -1t

Combine like terms: t + -1t = 0
-4 + 32t = -3 + 0
-4 + 32t = -3

Solving
-4 + 32t = -3

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 32t = -3 + 4

Combine like terms: -4 + 4 = 0
0 + 32t = -3 + 4
32t = -3 + 4

Combine like terms: -3 + 4 = 1
32t = 1

Divide each side by '32'.
t = 0.03125

Simplifying
t = 0.03125