8(4u+1)-12v=11(2v-6)

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Solution for 8(4u+1)-12v=11(2v-6) equation:


Simplifying
8(4u + 1) + -12v = 11(2v + -6)

Reorder the terms:
8(1 + 4u) + -12v = 11(2v + -6)
(1 * 8 + 4u * 8) + -12v = 11(2v + -6)
(8 + 32u) + -12v = 11(2v + -6)

Reorder the terms:
8 + 32u + -12v = 11(-6 + 2v)
8 + 32u + -12v = (-6 * 11 + 2v * 11)
8 + 32u + -12v = (-66 + 22v)

Solving
8 + 32u + -12v = -66 + 22v

Solving for variable 'u'.

Move all terms containing u to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + 32u + -8 + -12v = -66 + -8 + 22v

Reorder the terms:
8 + -8 + 32u + -12v = -66 + -8 + 22v

Combine like terms: 8 + -8 = 0
0 + 32u + -12v = -66 + -8 + 22v
32u + -12v = -66 + -8 + 22v

Combine like terms: -66 + -8 = -74
32u + -12v = -74 + 22v

Add '12v' to each side of the equation.
32u + -12v + 12v = -74 + 22v + 12v

Combine like terms: -12v + 12v = 0
32u + 0 = -74 + 22v + 12v
32u = -74 + 22v + 12v

Combine like terms: 22v + 12v = 34v
32u = -74 + 34v

Divide each side by '32'.
u = -2.3125 + 1.0625v

Simplifying
u = -2.3125 + 1.0625v

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