8(4u-1)-12v=(2v-6)

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Solution for 8(4u-1)-12v=(2v-6) equation:


Simplifying
8(4u + -1) + -12v = (2v + -6)

Reorder the terms:
8(-1 + 4u) + -12v = (2v + -6)
(-1 * 8 + 4u * 8) + -12v = (2v + -6)
(-8 + 32u) + -12v = (2v + -6)

Reorder the terms:
-8 + 32u + -12v = (-6 + 2v)

Remove parenthesis around (-6 + 2v)
-8 + 32u + -12v = -6 + 2v

Solving
-8 + 32u + -12v = -6 + 2v

Solving for variable 'u'.

Move all terms containing u to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 32u + 8 + -12v = -6 + 8 + 2v

Reorder the terms:
-8 + 8 + 32u + -12v = -6 + 8 + 2v

Combine like terms: -8 + 8 = 0
0 + 32u + -12v = -6 + 8 + 2v
32u + -12v = -6 + 8 + 2v

Combine like terms: -6 + 8 = 2
32u + -12v = 2 + 2v

Add '12v' to each side of the equation.
32u + -12v + 12v = 2 + 2v + 12v

Combine like terms: -12v + 12v = 0
32u + 0 = 2 + 2v + 12v
32u = 2 + 2v + 12v

Combine like terms: 2v + 12v = 14v
32u = 2 + 14v

Divide each side by '32'.
u = 0.0625 + 0.4375v

Simplifying
u = 0.0625 + 0.4375v

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