8(4v+2)=-3v+16

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Solution for 8(4v+2)=-3v+16 equation: 



8(4v+2)=-3v+16

We move all terms to the left:

8(4v+2)-(-3v+16)=0

We multiply parentheses

32v-(-3v+16)+16=0

We get rid of parentheses

32v+3v-16+16=0

We add all the numbers together, and all the variables

35v=0

v=0/35

v=0

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