8(4x+1)=23x+80

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Solution for 8(4x+1)=23x+80 equation: 



8(4x+1)=23x+80

We move all terms to the left:

8(4x+1)-(23x+80)=0

We multiply parentheses

32x-(23x+80)+8=0

We get rid of parentheses

32x-23x-80+8=0

We add all the numbers together, and all the variables

9x-72=0

We move all terms containing x to the left, all other terms to the right

9x=72

x=72/9

x=8

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