8(4x+1)=40

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Solution for 8(4x+1)=40 equation: 



8(4x+1)=40

We move all terms to the left:

8(4x+1)-(40)=0

We multiply parentheses

32x+8-40=0

We add all the numbers together, and all the variables

32x-32=0

We move all terms containing x to the left, all other terms to the right

32x=32

x=32/32

x=1

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