8(4x+1)=5(2z+1)

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Solution for 8(4x+1)=5(2z+1) equation:


Simplifying
8(4x + 1) = 5(2z + 1)

Reorder the terms:
8(1 + 4x) = 5(2z + 1)
(1 * 8 + 4x * 8) = 5(2z + 1)
(8 + 32x) = 5(2z + 1)

Reorder the terms:
8 + 32x = 5(1 + 2z)
8 + 32x = (1 * 5 + 2z * 5)
8 + 32x = (5 + 10z)

Solving
8 + 32x = 5 + 10z

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + 32x = 5 + -8 + 10z

Combine like terms: 8 + -8 = 0
0 + 32x = 5 + -8 + 10z
32x = 5 + -8 + 10z

Combine like terms: 5 + -8 = -3
32x = -3 + 10z

Divide each side by '32'.
x = -0.09375 + 0.3125z

Simplifying
x = -0.09375 + 0.3125z

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