8(4x+2)+x=(4x-2)4+3

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Solution for 8(4x+2)+x=(4x-2)4+3 equation: 



8(4x+2)+x=(4x-2)4+3

We move all terms to the left:

8(4x+2)+x-((4x-2)4+3)=0

We add all the numbers together, and all the variables

x+8(4x+2)-((4x-2)4+3)=0

We multiply parentheses

x+32x-((4x-2)4+3)+16=0



We calculate terms in parentheses: -((4x-2)4+3), so:

(4x-2)4+3

We multiply parentheses

16x-8+3

We add all the numbers together, and all the variables

16x-5

Back to the equation:

-(16x-5)



We add all the numbers together, and all the variables

33x-(16x-5)+16=0

We get rid of parentheses

33x-16x+5+16=0

We add all the numbers together, and all the variables

17x+21=0

We move all terms containing x to the left, all other terms to the right

17x=-21

x=-21/17

x=-1+4/17

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