8(4x+2)-(20x+14)=6(2x-4)+20

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Solution for 8(4x+2)-(20x+14)=6(2x-4)+20 equation: 



8(4x+2)-(20x+14)=6(2x-4)+20

We move all terms to the left:

8(4x+2)-(20x+14)-(6(2x-4)+20)=0

We multiply parentheses

32x-(20x+14)-(6(2x-4)+20)+16=0

We get rid of parentheses

32x-20x-(6(2x-4)+20)-14+16=0



We calculate terms in parentheses: -(6(2x-4)+20), so:

6(2x-4)+20

We multiply parentheses

12x-24+20

We add all the numbers together, and all the variables

12x-4

Back to the equation:

-(12x-4)



We add all the numbers together, and all the variables

12x-(12x-4)+2=0

We get rid of parentheses

12x-12x+4+2=0

We add all the numbers together, and all the variables

6!=0

There is no solution for this equation

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