8(4x+2)-6x-5=2(13x-4)+19

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Solution for 8(4x+2)-6x-5=2(13x-4)+19 equation: 



8(4x+2)-6x-5=2(13x-4)+19

We move all terms to the left:

8(4x+2)-6x-5-(2(13x-4)+19)=0

We add all the numbers together, and all the variables

-6x+8(4x+2)-(2(13x-4)+19)-5=0

We multiply parentheses

-6x+32x-(2(13x-4)+19)+16-5=0



We calculate terms in parentheses: -(2(13x-4)+19), so:

2(13x-4)+19

We multiply parentheses

26x-8+19

We add all the numbers together, and all the variables

26x+11

Back to the equation:

-(26x+11)



We add all the numbers together, and all the variables

26x-(26x+11)+11=0

We get rid of parentheses

26x-26x-11+11=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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