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8(4x+3)-5(6x-5)=4(9x+4)-7(4x-5)
We move all terms to the left:
8(4x+3)-5(6x-5)-(4(9x+4)-7(4x-5))=0
We multiply parentheses
32x-30x-(4(9x+4)-7(4x-5))+24+25=0
We calculate terms in parentheses: -(4(9x+4)-7(4x-5)), so:We add all the numbers together, and all the variables
4(9x+4)-7(4x-5)
We multiply parentheses
36x-28x+16+35
We add all the numbers together, and all the variables
8x+51
Back to the equation:
-(8x+51)
2x-(8x+51)+49=0
We get rid of parentheses
2x-8x-51+49=0
We add all the numbers together, and all the variables
-6x-2=0
We move all terms containing x to the left, all other terms to the right
-6x=2
x=2/-6
x=-1/3
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