8(4x+4)=2(3x-2)

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Solution for 8(4x+4)=2(3x-2) equation: 



8(4x+4)=2(3x-2)

We move all terms to the left:

8(4x+4)-(2(3x-2))=0

We multiply parentheses

32x-(2(3x-2))+32=0



We calculate terms in parentheses: -(2(3x-2)), so:

2(3x-2)

We multiply parentheses

6x-4

Back to the equation:

-(6x-4)



We get rid of parentheses

32x-6x+4+32=0

We add all the numbers together, and all the variables

26x+36=0

We move all terms containing x to the left, all other terms to the right

26x=-36

x=-36/26

x=-1+5/13

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