8(4x-1)=-80

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Solution for 8(4x-1)=-80 equation:



8(4x-1)=-80
We move all terms to the left:
8(4x-1)-(-80)=0
We add all the numbers together, and all the variables
8(4x-1)+80=0
We multiply parentheses
32x-8+80=0
We add all the numbers together, and all the variables
32x+72=0
We move all terms containing x to the left, all other terms to the right
32x=-72
x=-72/32
x=-2+1/4

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