8(4x-3)(6x+5)=0

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Solution for 8(4x-3)(6x+5)=0 equation:



8(4x-3)(6x+5)=0
We multiply parentheses ..
8(+24x^2+20x-18x-15)=0
We multiply parentheses
192x^2+160x-144x-120=0
We add all the numbers together, and all the variables
192x^2+16x-120=0
a = 192; b = 16; c = -120;
Δ = b2-4ac
Δ = 162-4·192·(-120)
Δ = 92416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{92416}=304$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-304}{2*192}=\frac{-320}{384} =-5/6 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+304}{2*192}=\frac{288}{384} =3/4 $

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