8(4x-5)-27=3(2x+5)

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Solution for 8(4x-5)-27=3(2x+5) equation: 



8(4x-5)-27=3(2x+5)

We move all terms to the left:

8(4x-5)-27-(3(2x+5))=0

We multiply parentheses

32x-(3(2x+5))-40-27=0



We calculate terms in parentheses: -(3(2x+5)), so:

3(2x+5)

We multiply parentheses

6x+15

Back to the equation:

-(6x+15)



We add all the numbers together, and all the variables

32x-(6x+15)-67=0

We get rid of parentheses

32x-6x-15-67=0

We add all the numbers together, and all the variables

26x-82=0

We move all terms containing x to the left, all other terms to the right

26x=82

x=82/26

x=3+2/13

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