8(4x-5)=4(8x+1)

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Solution for 8(4x-5)=4(8x+1) equation:


Simplifying
8(4x + -5) = 4(8x + 1)

Reorder the terms:
8(-5 + 4x) = 4(8x + 1)
(-5 * 8 + 4x * 8) = 4(8x + 1)
(-40 + 32x) = 4(8x + 1)

Reorder the terms:
-40 + 32x = 4(1 + 8x)
-40 + 32x = (1 * 4 + 8x * 4)
-40 + 32x = (4 + 32x)

Add '-32x' to each side of the equation.
-40 + 32x + -32x = 4 + 32x + -32x

Combine like terms: 32x + -32x = 0
-40 + 0 = 4 + 32x + -32x
-40 = 4 + 32x + -32x

Combine like terms: 32x + -32x = 0
-40 = 4 + 0
-40 = 4

Solving
-40 = 4

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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