8(4x-7)=-28

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Solution for 8(4x-7)=-28 equation: 



8(4x-7)=-28

We move all terms to the left:

8(4x-7)-(-28)=0

We add all the numbers together, and all the variables

8(4x-7)+28=0

We multiply parentheses

32x-56+28=0

We add all the numbers together, and all the variables

32x-28=0

We move all terms containing x to the left, all other terms to the right

32x=28

x=28/32

x=7/8

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