8(4y-11)+3y=19(6y+21)-91

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Solution for 8(4y-11)+3y=19(6y+21)-91 equation: 



8(4y-11)+3y=19(6y+21)-91

We move all terms to the left:

8(4y-11)+3y-(19(6y+21)-91)=0

We add all the numbers together, and all the variables

3y+8(4y-11)-(19(6y+21)-91)=0

We multiply parentheses

3y+32y-(19(6y+21)-91)-88=0



We calculate terms in parentheses: -(19(6y+21)-91), so:

19(6y+21)-91

We multiply parentheses

114y+399-91

We add all the numbers together, and all the variables

114y+308

Back to the equation:

-(114y+308)



We add all the numbers together, and all the variables

35y-(114y+308)-88=0

We get rid of parentheses

35y-114y-308-88=0

We add all the numbers together, and all the variables

-79y-396=0

We move all terms containing y to the left, all other terms to the right

-79y=396

y=396/-79

y=-5+1/79

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