8(5+2b)=-2-10(6-b)

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Solution for 8(5+2b)=-2-10(6-b) equation: 



8(5+2b)=-2-10(6-b)

We move all terms to the left:

8(5+2b)-(-2-10(6-b))=0

We add all the numbers together, and all the variables

8(2b+5)-(-2-10(-1b+6))=0

We multiply parentheses

16b-(-2-10(-1b+6))+40=0



We calculate terms in parentheses: -(-2-10(-1b+6)), so:

-2-10(-1b+6)

determiningTheFunctionDomain
-10(-1b+6)-2

We multiply parentheses

10b-60-2

We add all the numbers together, and all the variables

10b-62

Back to the equation:

-(10b-62)



We get rid of parentheses

16b-10b+62+40=0

We add all the numbers together, and all the variables

6b+102=0

We move all terms containing b to the left, all other terms to the right

6b=-102

b=-102/6

b=-17

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