8(5-2q)/3=7q+10

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Solution for 8(5-2q)/3=7q+10 equation: 



8(5-2q)/3=7q+10

We move all terms to the left:

8(5-2q)/3-(7q+10)=0

We add all the numbers together, and all the variables

8(-2q+5)/3-(7q+10)=0

We get rid of parentheses

8(-2q+5)/3-7q-10=0

We multiply all the terms by the denominator


8(-2q+5)-7q*3-10*3=0

We add all the numbers together, and all the variables

8(-2q+5)-7q*3-30=0

We multiply parentheses

-16q-7q*3+40-30=0

Wy multiply elements

-16q-21q+40-30=0

We add all the numbers together, and all the variables

-37q+10=0

We move all terms containing q to the left, all other terms to the right

-37q=-10

q=-10/-37

q=10/37

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