8(5C-2)=10(32+4C)

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Solution for 8(5C-2)=10(32+4C) equation: 


Simplifying
8(5C + -2) = 10(32 + 4C)

Reorder the terms:
8(-2 + 5C) = 10(32 + 4C)
(-2 * 8 + 5C * 8) = 10(32 + 4C)
(-16 + 40C) = 10(32 + 4C)
-16 + 40C = (32 * 10 + 4C * 10)
-16 + 40C = (320 + 40C)

Add '-40C' to each side of the equation.
-16 + 40C + -40C = 320 + 40C + -40C

Combine like terms: 40C + -40C = 0
-16 + 0 = 320 + 40C + -40C
-16 = 320 + 40C + -40C

Combine like terms: 40C + -40C = 0
-16 = 320 + 0
-16 = 320

Solving
-16 = 320

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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