8(5t+1)-10=t-(t+1)

Solution for 8(5t+1)-10=t-(t+1) equation:

Simplifying
8(5t + 1) + -10 = t + -1(t + 1)

Reorder the terms:
8(1 + 5t) + -10 = t + -1(t + 1)
(1 * 8 + 5t * 8) + -10 = t + -1(t + 1)
(8 + 40t) + -10 = t + -1(t + 1)

Reorder the terms:
8 + -10 + 40t = t + -1(t + 1)

Combine like terms: 8 + -10 = -2
-2 + 40t = t + -1(t + 1)

Reorder the terms:
-2 + 40t = t + -1(1 + t)
-2 + 40t = t + (1 * -1 + t * -1)
-2 + 40t = t + (-1 + -1t)

Reorder the terms:
-2 + 40t = -1 + t + -1t

Combine like terms: t + -1t = 0
-2 + 40t = -1 + 0
-2 + 40t = -1

Solving
-2 + 40t = -1

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 40t = -1 + 2

Combine like terms: -2 + 2 = 0
0 + 40t = -1 + 2
40t = -1 + 2

Combine like terms: -1 + 2 = 1
40t = 1

Divide each side by '40'.
t = 0.025

Simplifying
t = 0.025