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8(5x+1)+7(2x+3)=13(3x+5)+2(2x+4)
We move all terms to the left:
8(5x+1)+7(2x+3)-(13(3x+5)+2(2x+4))=0
We multiply parentheses
40x+14x-(13(3x+5)+2(2x+4))+8+21=0
We calculate terms in parentheses: -(13(3x+5)+2(2x+4)), so:We add all the numbers together, and all the variables
13(3x+5)+2(2x+4)
We multiply parentheses
39x+4x+65+8
We add all the numbers together, and all the variables
43x+73
Back to the equation:
-(43x+73)
54x-(43x+73)+29=0
We get rid of parentheses
54x-43x-73+29=0
We add all the numbers together, and all the variables
11x-44=0
We move all terms containing x to the left, all other terms to the right
11x=44
x=44/11
x=4
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