8(5x-2)=1-(32+4x)

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Solution for 8(5x-2)=1-(32+4x) equation: 



8(5x-2)=1-(32+4x)

We move all terms to the left:

8(5x-2)-(1-(32+4x))=0

We add all the numbers together, and all the variables

8(5x-2)-(1-(4x+32))=0

We multiply parentheses

40x-(1-(4x+32))-16=0



We calculate terms in parentheses: -(1-(4x+32)), so:

1-(4x+32)

determiningTheFunctionDomain
-(4x+32)+1

We get rid of parentheses

-4x-32+1

We add all the numbers together, and all the variables

-4x-31

Back to the equation:

-(-4x-31)



We get rid of parentheses

40x+4x+31-16=0

We add all the numbers together, and all the variables

44x+15=0

We move all terms containing x to the left, all other terms to the right

44x=-15

x=-15/44

x=-15/44

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