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8(5x-6)=3(x+1)
We move all terms to the left:
8(5x-6)-(3(x+1))=0
We multiply parentheses
40x-(3(x+1))-48=0
We calculate terms in parentheses: -(3(x+1)), so:We get rid of parentheses
3(x+1)
We multiply parentheses
3x+3
Back to the equation:
-(3x+3)
40x-3x-3-48=0
We add all the numbers together, and all the variables
37x-51=0
We move all terms containing x to the left, all other terms to the right
37x=51
x=51/37
x=1+14/37
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