8(5x-9)-7=4(2x-4)+8

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Solution for 8(5x-9)-7=4(2x-4)+8 equation: 



8(5x-9)-7=4(2x-4)+8

We move all terms to the left:

8(5x-9)-7-(4(2x-4)+8)=0

We multiply parentheses

40x-(4(2x-4)+8)-72-7=0



We calculate terms in parentheses: -(4(2x-4)+8), so:

4(2x-4)+8

We multiply parentheses

8x-16+8

We add all the numbers together, and all the variables

8x-8

Back to the equation:

-(8x-8)



We add all the numbers together, and all the variables

40x-(8x-8)-79=0

We get rid of parentheses

40x-8x+8-79=0

We add all the numbers together, and all the variables

32x-71=0

We move all terms containing x to the left, all other terms to the right

32x=71

x=71/32

x=2+7/32

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