8(5y-2)=10(32+4y)

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Solution for 8(5y-2)=10(32+4y) equation: 


Simplifying
8(5y + -2) = 10(32 + 4y)

Reorder the terms:
8(-2 + 5y) = 10(32 + 4y)
(-2 * 8 + 5y * 8) = 10(32 + 4y)
(-16 + 40y) = 10(32 + 4y)
-16 + 40y = (32 * 10 + 4y * 10)
-16 + 40y = (320 + 40y)

Add '-40y' to each side of the equation.
-16 + 40y + -40y = 320 + 40y + -40y

Combine like terms: 40y + -40y = 0
-16 + 0 = 320 + 40y + -40y
-16 = 320 + 40y + -40y

Combine like terms: 40y + -40y = 0
-16 = 320 + 0
-16 = 320

Solving
-16 = 320

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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