8(6+4/5b)=(9/10b)8

Solution for 8(6+4/5b)=(9/10b)8 equation:

8(6+4/5b)=(9/10b)8

We move all terms to the left:

8(6+4/5b)-((9/10b)8)=0


Domain of the equation: 5b)!=0

b!=0/1

b!=0

b∈R



Domain of the equation: 10b)8)!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

8(4/5b+6)-((+9/10b)8)=0

We multiply parentheses

32b-((+9/10b)8)+48=0

We multiply all the terms by the denominator


32b*10b)8)-((+48*10b)8)+9=0

Wy multiply elements

320b^2+480b=0

a = 320; b = 480; c = 0;
Δ = b2-4ac
Δ = 4802-4·320·0
Δ = 230400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{230400}=480$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(480)-480}{2*320}=\frac{-960}{640}
=-1+1/2
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(480)+480}{2*320}=\frac{0}{640}
=0
$