8(6+4x)=8-12(3+2)

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Solution for 8(6+4x)=8-12(3+2) equation: 



8(6+4x)=8-12(3+2)

We move all terms to the left:

8(6+4x)-(8-12(3+2))=0

We add all the numbers together, and all the variables

8(4x+6)-(8-125)=0

We add all the numbers together, and all the variables

8(4x+6)+117=0

We multiply parentheses

32x+48+117=0

We add all the numbers together, and all the variables

32x+165=0

We move all terms containing x to the left, all other terms to the right

32x=-165

x=-165/32

x=-5+5/32

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