8(6-a)=8a+(4-a)

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Solution for 8(6-a)=8a+(4-a) equation: 



8(6-a)=8a+(4-a)

We move all terms to the left:

8(6-a)-(8a+(4-a))=0

We add all the numbers together, and all the variables

8(-1a+6)-(8a+(-1a+4))=0

We multiply parentheses

-8a-(8a+(-1a+4))+48=0



We calculate terms in parentheses: -(8a+(-1a+4)), so:

8a+(-1a+4)

We get rid of parentheses

8a-1a+4

We add all the numbers together, and all the variables

7a+4

Back to the equation:

-(7a+4)



We get rid of parentheses

-8a-7a-4+48=0

We add all the numbers together, and all the variables

-15a+44=0

We move all terms containing a to the left, all other terms to the right

-15a=-44

a=-44/-15

a=2+14/15

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