8(6-x)=8x+8(4-x)

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Solution for 8(6-x)=8x+8(4-x) equation: 



8(6-x)=8x+8(4-x)

We move all terms to the left:

8(6-x)-(8x+8(4-x))=0

We add all the numbers together, and all the variables

8(-1x+6)-(8x+8(-1x+4))=0

We multiply parentheses

-8x-(8x+8(-1x+4))+48=0



We calculate terms in parentheses: -(8x+8(-1x+4)), so:

8x+8(-1x+4)

We multiply parentheses

8x-8x+32

We add all the numbers together, and all the variables

32

Back to the equation:

-(32)



We add all the numbers together, and all the variables

-8x+16=0

We move all terms containing x to the left, all other terms to the right

-8x=-16

x=-16/-8

x=+2

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