8(6b+3)=8/7(21+42b)

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Solution for 8(6b+3)=8/7(21+42b) equation:



8(6b+3)=8/7(21+42b)
We move all terms to the left:
8(6b+3)-(8/7(21+42b))=0
Domain of the equation: 7(21+42b))!=0
b∈R
We add all the numbers together, and all the variables
8(6b+3)-(8/7(42b+21))=0
We multiply parentheses
48b-(8/7(42b+21))+24=0
We multiply all the terms by the denominator
48b*7(42b+21))-(8+24*7(42b+21))=0
Wy multiply elements
336b^2(4+168b(4=0

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