8(6b+3)=8/7(21+42b)

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Solution for 8(6b+3)=8/7(21+42b) equation: 



8(6b+3)=8/7(21+42b)

We move all terms to the left:

8(6b+3)-(8/7(21+42b))=0



Domain of the equation: 7(21+42b))!=0

b∈R



We add all the numbers together, and all the variables

8(6b+3)-(8/7(42b+21))=0

We multiply parentheses

48b-(8/7(42b+21))+24=0

We multiply all the terms by the denominator


48b*7(42b+21))-(8+24*7(42b+21))=0

Wy multiply elements

336b^2(4+168b(4=0

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