8(6x+5)+5(9x+7)=2(3x-4)-8(4x-3)

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Solution for 8(6x+5)+5(9x+7)=2(3x-4)-8(4x-3) equation:



8(6x+5)+5(9x+7)=2(3x-4)-8(4x-3)
We move all terms to the left:
8(6x+5)+5(9x+7)-(2(3x-4)-8(4x-3))=0
We multiply parentheses
48x+45x-(2(3x-4)-8(4x-3))+40+35=0
We calculate terms in parentheses: -(2(3x-4)-8(4x-3)), so:
2(3x-4)-8(4x-3)
We multiply parentheses
6x-32x-8+24
We add all the numbers together, and all the variables
-26x+16
Back to the equation:
-(-26x+16)
We add all the numbers together, and all the variables
93x-(-26x+16)+75=0
We get rid of parentheses
93x+26x-16+75=0
We add all the numbers together, and all the variables
119x+59=0
We move all terms containing x to the left, all other terms to the right
119x=-59
x=-59/119
x=-59/119

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