8(7+4n)+7n=290

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Solution for 8(7+4n)+7n=290 equation: 



8(7+4n)+7n=290

We move all terms to the left:

8(7+4n)+7n-(290)=0

We add all the numbers together, and all the variables

8(4n+7)+7n-290=0

We add all the numbers together, and all the variables

7n+8(4n+7)-290=0

We multiply parentheses

7n+32n+56-290=0

We add all the numbers together, and all the variables

39n-234=0

We move all terms containing n to the left, all other terms to the right

39n=234

n=234/39

n=6

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