8(7-3x)+1=4(2-x)(2+x)

Solution for 8(7-3x)+1=4(2-x)(2+x) equation:

8(7-3x)+1=4(2-x)(2+x)

We move all terms to the left:

8(7-3x)+1-(4(2-x)(2+x))=0

We add all the numbers together, and all the variables

8(-3x+7)-(4(-1x+2)(x+2))+1=0

We multiply parentheses

-24x-(4(-1x+2)(x+2))+56+1=0

We multiply parentheses ..

-(4(-1x^2-2x+2x+4))-24x+56+1=0


We calculate terms in parentheses: -(4(-1x^2-2x+2x+4)), so:

4(-1x^2-2x+2x+4)

We multiply parentheses

-4x^2-8x+8x+16

We add all the numbers together, and all the variables

-4x^2+16

Back to the equation:

-(-4x^2+16)


We add all the numbers together, and all the variables

-(-4x^2+16)-24x+57=0

We get rid of parentheses

4x^2-24x-16+57=0

We add all the numbers together, and all the variables

4x^2-24x+41=0

a = 4; b = -24; c = +41;
Δ = b2-4ac
Δ = -242-4·4·41
Δ = -80
Delta is less than zero, so there is no solution for the equation