8(7-3x)+7(7x+5)=41

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Solution for 8(7-3x)+7(7x+5)=41 equation: 



8(7-3x)+7(7x+5)=41

We move all terms to the left:

8(7-3x)+7(7x+5)-(41)=0

We add all the numbers together, and all the variables

8(-3x+7)+7(7x+5)-41=0

We multiply parentheses

-24x+49x+56+35-41=0

We add all the numbers together, and all the variables

25x+50=0

We move all terms containing x to the left, all other terms to the right

25x=-50

x=-50/25

x=-2

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