8(7a+1)=-40+8a

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Solution for 8(7a+1)=-40+8a equation: 



8(7a+1)=-40+8a

We move all terms to the left:

8(7a+1)-(-40+8a)=0

We add all the numbers together, and all the variables

8(7a+1)-(8a-40)=0

We multiply parentheses

56a-(8a-40)+8=0

We get rid of parentheses

56a-8a+40+8=0

We add all the numbers together, and all the variables

48a+48=0

We move all terms containing a to the left, all other terms to the right

48a=-48

a=-48/48

a=-1

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