8(7c-10)-6=6c+6+4c

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Solution for 8(7c-10)-6=6c+6+4c equation: 



8(7c-10)-6=6c+6+4c

We move all terms to the left:

8(7c-10)-6-(6c+6+4c)=0

We add all the numbers together, and all the variables

8(7c-10)-(10c+6)-6=0

We multiply parentheses

56c-(10c+6)-80-6=0

We get rid of parentheses

56c-10c-6-80-6=0

We add all the numbers together, and all the variables

46c-92=0

We move all terms containing c to the left, all other terms to the right

46c=92

c=92/46

c=2

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