8(7x+5)=40-x

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Solution for 8(7x+5)=40-x equation: 



8(7x+5)=40-x

We move all terms to the left:

8(7x+5)-(40-x)=0

We add all the numbers together, and all the variables

8(7x+5)-(-1x+40)=0

We multiply parentheses

56x-(-1x+40)+40=0

We get rid of parentheses

56x+1x-40+40=0

We add all the numbers together, and all the variables

57x=0

x=0/57

x=0

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