8(7y-5)+30=56y-10

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Solution for 8(7y-5)+30=56y-10 equation: 



8(7y-5)+30=56y-10

We move all terms to the left:

8(7y-5)+30-(56y-10)=0

We multiply parentheses

56y-(56y-10)-40+30=0

We get rid of parentheses

56y-56y+10-40+30=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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