8(8+4x)-3x=-7(7x+2)

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Solution for 8(8+4x)-3x=-7(7x+2) equation: 



8(8+4x)-3x=-7(7x+2)

We move all terms to the left:

8(8+4x)-3x-(-7(7x+2))=0

We add all the numbers together, and all the variables

8(4x+8)-3x-(-7(7x+2))=0

We add all the numbers together, and all the variables

-3x+8(4x+8)-(-7(7x+2))=0

We multiply parentheses

-3x+32x-(-7(7x+2))+64=0



We calculate terms in parentheses: -(-7(7x+2)), so:

-7(7x+2)

We multiply parentheses

-49x-14

Back to the equation:

-(-49x-14)



We add all the numbers together, and all the variables

29x-(-49x-14)+64=0

We get rid of parentheses

29x+49x+14+64=0

We add all the numbers together, and all the variables

78x+78=0

We move all terms containing x to the left, all other terms to the right

78x=-78

x=-78/78

x=-1

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