8(8-4x)=-12+6x

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Solution for 8(8-4x)=-12+6x equation: 



8(8-4x)=-12+6x

We move all terms to the left:

8(8-4x)-(-12+6x)=0

We add all the numbers together, and all the variables

8(-4x+8)-(6x-12)=0

We multiply parentheses

-32x-(6x-12)+64=0

We get rid of parentheses

-32x-6x+12+64=0

We add all the numbers together, and all the variables

-38x+76=0

We move all terms containing x to the left, all other terms to the right

-38x=-76

x=-76/-38

x=+2

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